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16 October, 01:49

A percent composition analysis yields 46.7% nitrogen and 53.3% oxygen. What is the empirical formula for the compound

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  1. 16 October, 03:31
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    Empirical formula is the simplest ratio of whole numbers of components in a compound

    calculating for 100 g of compound

    N O

    mass 46.7 g 53.3 g

    number of moles 46.7 g / 14 g/mol 53.3 g / 16 g/mol

    = 3.33 = 3.33

    divide by the least number of moles

    3.33 / 3.33 = 1.00 3.33/3.33 = 0

    number of atoms

    N - 1

    O - 1

    therefore empirical formula is NO
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