How much heat is required to warm 1.50 kg of sand from 30.0 ∘c to 100.0∘c? the heat capacity of sand is 0.84 j⋅g-1⋅k-1?

Question

Chemistry

Ayers

15 June, 04:21

How much heat is required to warm 1.50 kg of sand from 30.0 ∘c to 100.0∘c? the heat capacity of sand is 0.84 j⋅g-1⋅k-1?

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Luke Summers · Answer 1

Answer is: the amount of heat required to warm the sand is 88.2 kJ.

m (sand) = 1,5 kg · 1000 g/kg = 1500 g.

ΔT = 100°C - 30°C = 70°C.

C (sand) = 0,84 J/g·°C.

Q = m (sand) · ΔT · C (sand).

Q = 1500 g · 70°C · 0,84 J/g·°C.

Q = 88200 J : 1000 J/kJ = 88,200 kJ.