A cabr2 solution has a concentration of 4m. what is the concentration if 2 l of the solution are mixed with 6 l of water?

We can use the dilution equation to find the new concentration of the solution

c1v1 = c2v2

where c1 is concentration and v1 is volume of the concentrated solution

c2 is concentration and v2 is volume of the diluted solution prepared

c1 - 4 M

v1 - 2 L of the concentrated solution is taken to be diluted

v2 - final volume of diluted solution - 2 L + 6 L = 8 L

substituting these values

4 M x 2 L = C x 8 L

C = 1 M

new concentration of the diluted solution is 1 M