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29 October, 21:12

Phosphine, an extremely poisonous and highly reactive gas, reacts with oxygen gas to form tetraphosphorus decaoxide and water. ph3 (g) + o2 (g) → p4o10 (s) + h2o (g) [unbalanced] calculate the mass of p4o10 (s) formed when 225 g of ph3 reacts with excess oxygen.

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  1. 29 October, 23:35
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    The molar mass of PH3 is 34 g/mol, therefore the moles is:

    moles PH3 = 225 g / (34 g/mol)

    moles PH3 = 6.62 mol

    The balanced equation is:

    4PH3 (g) + 8O2 (g) → P4O10 (g) + 6H2O

    We see that 4 mol of PH3 is required for every mol of P4O10, therefore the number of moles of P4O10 is:

    moles P4O10 = 6.62 mol * (1/4)

    moles P4O10 = 1.65 mol

    The molar mass of P4O10 is 283.89 g/mol, so the mass is:

    mass P4O10 = 1.65 mol * 283.89 g/mol

    mass P4O10 = 469.67 grams ~ 470 grams
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