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6 March, 23:02

Convert 345 NH3 grams to moles

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Answers (2)
  1. 7 March, 02:34
    0
    M (NH₃) = 345 g

    M (NH₃) = A (N) + 3A (H)

    M (NH₃) = 14.0+3·1.0=17.0g/mol

    n (NH₃) = m (NH₃) / M (NH₃)

    n (NH₃) = 345g/17.0g/mol=20.3 mol
  2. 7 March, 02:46
    0
    345 NH3 in moles is: 20.2577490294015 moles.
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