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13 May, 12:32

Calculate the enthalpy change for the reaction 2 hcl → h2 + cl2 1. + 184 kj/mol of rxn 2. + 428 kj/mol of rxn 3. 0 kj/mol of rxn 4. - 184 kj/mol of rxn 5. - 244 kj/mol of rxn

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  1. 13 May, 13:13
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    Below is the list of enthalpies of formation of the compounds involved in the chemical reaction.

    HCl: - 92.3 kJ/mol

    H2: 0

    Cl2: 0

    Both H2 and Cl2 do not have enthaply of formation because they are pure substances.

    Since, in the reaction there are 2 moles of HCl,

    Enthalphy of formation = enthalpy of products - enthalphy of reactant/s

    = 0 - (-92.3) (2) = + 184.6 kJ

    Hence, the answer is the first choice.
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