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3 November, 20:26

By titration, 20.4 ml of aqueous h2so4 neutralized 23.3 ml of 0.0336 m lioh solution. what was the molarity of the aqueous acid solution?

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  1. 4 November, 00:10
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    The balanced equation for the neutralisation reaction is as follows

    2LiOH + H₂SO₄ - - - > Li₂SO₄ + 2H₂O

    stoichiometry of LiOH to H₂SO₄ is 2:1

    number of moles of LiOH moles reacted - 0.0336 mol/L x 0.0233 L = 7.83 x 10⁻⁴ mol

    if 2 mol of LiOH reacts with 1 mol of H₂SO₄

    then 7.83 x 10⁻⁴ mol of LiOH reacts with - 7.83 x 10⁻⁴ / 2 mol = 3.92 x 10⁻⁴ mol of H₂SO₄

    if 20.4 mL contains - 3.92 x 10⁻⁴ mol of H₂SO₄

    then 1000 mL contains - 3.92 x 10⁻⁴ mol / 20.4 mL x 1000 mL / L = 0.0192 mol/L

    molarity of H₂SO₄ solution - 0.0192 M
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