Calculate the standard cell potential at 25 ∘c for the reaction x (s) + 2y + (aq) →x2 + (aq) + 2y (s) where δh∘ = - 793 kj and δs∘ = - 319 j/k. express your answer to three significant figures and include the appropriate

First we will calculate free energy change:

ΔG₀ = ΔH₀ - (T * ΔS₀)

= - 793 kJ - (298 * - 0.319 kJ/K) = - 698 kJ

We know the relation between free energy change and cell potential is:

ΔG₀ = - n F E⁰ where

F = Faraday's constant = 96485 C/mol

n = 2 (given by equation that the electrons involved is 2)

ΔG₀ = - 2 x 96485 x E⁰

- 698 kJ = - 2 x 96485 x E⁰

E⁰ = (698 x 1000) / (2 x 96485) = 3.62 volts