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10 October, 10:50

What volume of 0.120 M HNO3 (qq) is needed to completely neutralize 150.0 milliliters of 0.100 M NaOH (aq)

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  1. 10 October, 14:34
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    Balanced equation for the neutralisation reaction is as follows

    NaOH + HNO₃ - - > NaNO₃ + H₂O

    stoichiometry of NaOH to HNO₃ is 1:1

    number of NaOH moles to be neutralised is - 0.100 mol/L x 0.1500 L = 0.015 mol

    therefore number of HNO₃ moles reacted - 0.015 mol

    molarity of HNO₃ solution is 0.120 M

    volume of solution in which there 0.120 mol - 1 L

    then 0.015 mol are in - 0.015 mol / 0.120 mol/L = 125 mL

    volume of HNO₃ required - 125 mL
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