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29 April, 12:41

What mass of co2 would be produced by the neutralization of 25.0 ml of 6.00m h2so4 using excess nahco3?

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  1. 29 April, 16:08
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    The complete balanced reaction is:

    H2SO4 + 2NaHCO3 - - > Na2SO4 + 2H2O + 2CO2

    Then we calculate the number of moles of H2SO4:

    moles H2SO4 = 0.025 L * 6 moles / L = 0.15 moles

    From stoichiometry of the balanced equation:

    moles CO2 = 0.15 moles H2SO4 * (2 moles CO2 / 1 mole H2SO4) = 0.30 moles

    The molar mass of CO2 is 44 g / mol, therefore the mass produced is:

    mass CO2 = 0.30 moles * (44 g / mol) = 13.2 g CO2

    Answer:

    13.2 g CO2
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