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16 June, 08:34

What is the mass of strontium chloride that reacts with 300.0 g of sulfuric acid?

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  1. 16 June, 11:25
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    SrCl₂ reacts with conc. H₂SO₄ and gives SrSO₄ and 2HCl as the products. The balanced equation is

    SrCl₂ + H ₂SO₄ → SrSO ₄ + 2HCl

    moles = mass / molar mass

    molar mass of H₂SO₄ = 98 g mol⁻¹

    moles of H₂SO₄ = 300.0 g / 98 g mol⁻¹ = 3.06 mol

    Stoichiometric ratio between SrCl₂ and H₂SO₄ is 1 : 1

    Hence, moles of SrCl₂ = moles of H₂SO₄

    = 3.06 mol

    molar mass of SrCl₂ = 158.53 g mol⁻¹

    Hence, mass of SrCl₂ = 3.06 mol x 158.53 g mol⁻¹

    = 485.1 g

    Hence, the mass of SrCl₂ needed to react with H₂SO₄ is 485.1 g
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