What is the temperature of a 1.59 L flask containing 0.175 mol of Ne at a pressure of 1.09 atm?

We can use the ideal gas law equation;

PV = nRT

P - pressure, V - volume, R - universal gas constant, n - number of moles and T - temperature

P - 1 atm - 101 325 Pa

1.09 atm - 1.09 atm x 101 325 Pa/atm = 110 444 Pa

n - 0.175 mol

V - 1.59 x 10⁻³ m³

substituting the values in the equation

110 444 Pa x 1.59 x 10⁻³ m³ = 0.175 mol x 8.314 Jmol⁻¹K⁻¹ x T

T = 120.70 K