What is the molarity of a solution that contains 2.35 g of nh3 in 0.0500 l of solution?

The molarity is the number of moles in 1 L of the solution.

The mass of NH₃ given - 2.35 g

Molar mass of NH₃ - 17 g/mol

The number of NH₃ moles in 2.35 g - 2.35 g / 17 g/mol = 0.138 mol

The number of moles in 0.05 L solution - 0.138 mol

Therefore number of moles in 1 L - 0.138 mol / 0.05 L x 1L = 2.76 mol

Therefore molarity of NH₃ - 2.76 M