A mixture 21.7 g NaCl 3.74 g kcl and 9.76 g licl how many moles of nacl are in this mixture

Moles (mol) = mass (g) / molar mass (g/mol)

Mass of NaCl = 21.7 g

Molar mass of NaCl = 58.4 g/mol

Hence, moles of NaCl = 21.7 g / 58.4 g/mol = 0.372 mol

Hence moles of NaCl in the mixture is 0.372 mol.

Let's assume that mixture has only given compounds and free of impurities.

Then, we can present this as a mole percentage.

mole % = (moles of desired substance / Total moles of the mixture) x 100%

Hence,

mole % of NaCl = (moles of NaCl / Total moles of the mixture) x 100%

Total moles of mixture = moles of NaCl + KCl + LiCl

Mass of KCl = 3.74 g

Molar mass of NaCl = 74.6 g/mol

Hence, moles of NaCl = 3.74 g / 74.6 g/mol = 0.050 mol

Mass of NaCl = 9.76 g

Molar mass of NaCl = 42.4 g/mol

Hence, moles of NaCl = 9.76 g / 42.4 g/mol = 0.230 mol

Total moles = 0.372 mol + 0.050 mol + 0.230 mol = 0.652 mol

mole % of NaCl = (moles of NaCl / Total moles of the mixture) x 100%

= (0.372 mol / 0.652 mol) x 100%

= 57.06%

Hence, mixture has 57.06% of NaCl as the mole percentage.