What is the molarity of a 10.2 % by mass glucose (c6h12o6) solution? (the density of the solution is 1.03 g/ml.) ?

Molality = moles of solute divided by kilograms of solvent In this case let’s assume a 100g sample solution: Since its 10.5% by mass, there is 10.5g glucose. The rest of the 89.5g is water. Divide the 10.5g glucose by its molar mass (180g) to get the # of moles, which is 0.058moles So now we have 0.058mole glucose divided by 0.089kilograms of water: the answer is 0.65molal