What is the volume of 10.5 moles of nitrogen gas at STP

The volume of 10.5 moles of nitrogen at standard temperature and pressure (STP) would be 235.33 L. Calculating this value, we assume that the gas is ideal so we use the equation PV = nRT. At STP, temperature is 273.15 K and pressure is 1 atm. We calculate as follows:

V = nRT / P

V = 10.5 (0.08205) (273.15) / 1

V = 235.33 L

The volume of 10.5 moles of nitrogen gas at STP (Standard Temperature and Pressure) is 235.339 liter of gas. This problem can be solved by using the PV=nRT or V = nRT/V equation which is the relation between the molar volume, the temperature, and the pressure of gas. In this formula, P is the pressure (1 atm @STP), R is the universal gas constant (0.0821 atm L/mol K), n is the molecule amount (10.5), V is the molecular volume, and T is the temperature (273 K @STP).

The calculation for the problem above: 10.5*0.0821*273/1 = 235.339