A 10g mass of krypton occupies 15.0 l at avpressure of 210 kpa. find the volume

From Boyle's law, we can use the equation

P1V1 = P2V2

to find the volume when the pressure is increased to 760 kPa:

V2 = P1V1 / P2

V2 = (210 kPa) (15.0 L) / 760 kPa

V2 = 4.14 Liters

Therefore, the volume is 3.99 Liters after the pressure increased to 760 kPa.

But if the pressure is increased to 790 kPa, the volume of the krypton will decrease to

V2 = P1V1 / P2

V2 = (210 kPa) (15.0 L) / 790 kPa

V2 = 3.99 Liters