Find the empirical formula of a compound containing 53.70% iron and 46.30% sulfur

SThe empirical formula is calculated as follows

calculate the moles of each element

moles = % composition/molar mass of element

that is iron (Fe) = 53.70/55.86 = 0.96 moles

Sulfur (s) = 46.30/32.07 = 1.44 moles

calculate the mole ratio by diving each mole by smallest mole (0.96)

that is Fe = 0.96/0/96 = 1

S = 1.44/0/96 = 1.5

multiply by 2 to remove decimal

that is Fe = 1 x 2 = 2

S = 1.5 x2 = 3

the empirical formula is therefore = Fe2S3