Ask Question
11 December, 08:32

If 8.60 grams of methane gas (hint: remember the fuel for the bunsen burner) is in a 2.00 L container at 66oC, what is the pressure in the container?

+3
Answers (1)
  1. 11 December, 12:24
    0
    dа ta:

    Gas: methane = CH4

    V = 2.00 liter

    T = 66°C = 66 + 273.15 K = 339.15 K

    Use the ideal gas equation pV = n RT

    R = 0.082 atm*liter / K*mol

    n is the number of moles and is calculated using the molar mass, MM, of CH4.

    MM of CH4 = 12.0 g/mol + 4*1 g/mol = 16.0 g / mol

    n = mass / MM = 8.60 g / 16.0 g/mol = 0.5375 mol

    Now you can use the formula: pV = nRT = > p = nRT / V

    p = 0.5375 mol * 0.082 atm*liter / K*mol * 339.15 K / 2.00 liter

    p = 7.47 atm
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “If 8.60 grams of methane gas (hint: remember the fuel for the bunsen burner) is in a 2.00 L container at 66oC, what is the pressure in the ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers