A solution contains 85.0 g of nano3, and has a volume of 750. ml. find the molarity of the solution

Molarity is defined as the number of moles in 1 L of solution.

Mass of NaNO₃ present - 85.0 g

Molar mass of NaNO₃ - 85 g/mol

The number of NaNO₃ moles - 85.0 g / 85 g/mol = 1 mol

Volume of solution - 750 mL

The number of moles in 0.750 mL - 1 mol

Therefore in 1 L solution, number of NaNO₃ moles - 1/0.75 = 1.33 mol

Therefore molarity of solution - 1.33 M