Ask Question
4 August, 12:48

How would you calculate the % yield of hydrogen if 40.0 grams of magnesium react with an excess of nitric acid producing 1.70 grams of hydrogen gas. mg + 2hno3 → mg (no 3) 2 + h?

+1
Answers (1)
  1. 4 August, 15:00
    0
    Magnesium in grams = 40 Actual yield is 1.70grams Calculating the yield based on the equation and moles, = 40g of Mn x (H2 (2.018g) / Mg (24.3g)) = 40 x 0.083 g H2 = 3.32g H2 Hydrogen % yield = (actual yield / calculated yield) x 100 = (1.70 / 3.32) x 100 Hydrogen % yield = 51.2%
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “How would you calculate the % yield of hydrogen if 40.0 grams of magnesium react with an excess of nitric acid producing 1.70 grams of ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers