Quicklime, CaO, can be prepared by roasting CaCO3 to produce Ca0 and CO2 When 2.00 X 10^3 grams of Calcium carbonate are heated, 1.05 X 10^3 grams of Calcium oxide is collected. What is the percentage yield?

Percentage yield = (actual yield / theoretical yield) x 100%

The balanced equation for the reaction is

CaCO₃ (s) → CaO (s) + CO₂ (g)

Moles = mass / molar mass

Mass of CaCO₃ (s) used = 2.00 x 10³ g

Molar mass of CaCO₃ (s) = 100.0 g/mol

Moles of CaCO₃ (s) = 2.00 x 10³ g / 100.0 g/mol

= 20.0 mol

Stoichiometric ratio between CaCO₃ (s) and CaO (s) is 1 : 1

Hence, moles of CaO = moles of CaCO₃ (s)

= 20.0 mol

Molar mass of CaO = 56.0 g/mol

Mass of CaO = 20.0 mol x 56.0 g/mol

= 1120 g

Hence, theoretical yield of CaO = 1120 g

Actual yield = 1.05 x 10³ g = 1050 g

Percentage yield = (1050 g / 1120 g) x 100%

= 93.75%

Hence, percentage yield of CaO is 93.75%