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23 May, 08:30

Find the molarity of 750 ml solution containing 346 g of potassium nitrate

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  1. 23 May, 11:15
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    Given mass of KNO₃=346g

    Molar mass of KNO₃ = (39.098) + (14) + (15.99*3) = 101.068gmol⁻¹

    Volume of Solution=750ml=0.75dm³

    Molarity = (mass of solute/molar mass of solute) * (1/volume of sol. in dm³)

    = (346/101.068) * (1/0.75)

    =4.56 mol dm⁻³
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