How much water would you add to 175ml of 6.00 m hydrochloric acid to prepare a 2.00 m solution of this acid?

We can use the dilution formula to find the volume of the diluted solution to be prepared first

c1v1 = c2v2

where c1 - concentration and v1 - volume of the concentrated solution

c2 - concentration and v2 - volume of the diluted solution

substituting the values

6.00 M x 175 mL = 2.00 M x V

V = 525 mL

volume of diluted solution is 525 mL

then volume of 6.00 M HCl acid taken is 175 mL

therefore volume of water to be added is - 525 - 175 = 350 mL

350 mL of water should be added