How many equivalents are present in 5.0 g of al3+?

The one definition of an equivalent weight that I know is that it is the amount of electrons which a substance gains or loses per mole.

Al3 + has + 3 charge therefore it loses 3 e-, so we can say that there are 3 equivalent weights in 1 mol Al3+.

1 mol Al3 + = 3 eq. wts.

1 mol Al x (27 g / 1 mol) x (1 mol / 3 eq. wts.) = 9.0 g = 1 eq. wt.

Answer:

5.0 g Al3 + x (1 eq. wt. / 9.0 g) = 0.56 eq. wts.