An apprentice jeweler determines the density of a sample of pure gold to be 20.3 g/cm3. the accepted value is 19.3 g/cm3. what is the percent error of the jeweler's density measurement?

We are tasked to find the percent error of the jeweler's density measurement through the formula:

%Error = Absolute Value (Experimental Value - Theoretical value) x 100% / Theoretical Value

We are given by the problem,

Experimental Value=20.3 g/cm3

Theoretical Value = 19.3 g/cm3

By Substituting the details,

%Error = Absolute Value (20.3 g/cm3 - 19.3 g/cm3) x 100% / 19.3 g/cm3

%Error=Absolute Value (1) / 19.3

%Error = 100/19.3

%Error = 5.18%

Therefore, 5.18% is the percent error committed by the jeweler

accepted value - experimental value / accepted value * 100 = percent error (19.3 g/cm3 - 20.3 g/cm3) / (19.3 g/cm3) * 100% = 5.18 g/cm3