What volume of 0.225 m k3po4 solution is necessary to completely react with 134 ml of 0.0112 m nicl2?

To answer this question, you need to know the equation for the reaction. The equation should look like this:

2K3PO4 (aq) + 3NiCl2 (aq) - - > Ni3 (PO4) 2 (s) + 6KCl (aq)

In the equation, 2 K3PO4 would react with 3 NiCl2. Then the calculation should be look like this:

V2 = V1*m1/m2 * 2/3

V2 = 134ml * 0.0112 / 0.225 * 2/3

V2 = 4.46ml