How much energy will be released from burning 230.0 g of liquid methanol (CH4O) in excess oxygen.

The molar mass of methanol is 12.01 + 4.04 + 16 = 32.05 g/mol

230.0 g of methanol / 32.05 g/mol = 7.176 mol methanol

The heat of combustion of methanol (CH3OH or CH4O) is - 715.0 kJ/mol. (Negative sign means the energy is released)

Multiplying 7.176 mol by - 715.0 kJ/mol gives - 5,131 kJ.