Ask Question
11 September, 21:09

Consider the positions of barium (Ba), sulfur (S), silicon (Si), and calcium (Ca) on the periodic table. The atoms of which element require the least amount of energy to give up an electron when forming chemical bonds?

+5
Answers (1)
  1. 11 September, 21:55
    0
    Element atomic number position

    Ba 56 group 2, period 6

    Ca 12 group 2, period 3

    S 16 group 16, period 3

    Si '14 group 14, period 3

    Now, you need to know the properties of the different type of elements and the tendencies on the periodic table.

    The metallic elements are, those placed on the left side of the periodic table, are the ones that release an electron more easily, so they will requiere less energy to give it up when forming chemical bonds.

    The higher the metallic character the less the energy need to give up an electron.

    The metallic character grows as the group number decreases (goes to the left) period increases (goes downward), so among the elements considered, Barium will require the least amount of energy to give un an electron when forming chemical bonds.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Consider the positions of barium (Ba), sulfur (S), silicon (Si), and calcium (Ca) on the periodic table. The atoms of which element require ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers