How many atoms of potassium are in 0.250 mol of potassium carbonate, k2co3?

The number of potassium atom that are in 0.25 moles potassium carbonate is calculated as follows

by use of Avogadro contant

1 mole = 6.02 x10^23 atoms

what about 0.25 moles,

by close multiplication

{0.250 moles x 6.02 x10^23} / 1 mole = 1.505 x10^23 atoms