How many moles of pcl5 can be produced from 23.0 g of p4 (and excess cl2) ? express your answer to three significant figures and include the appropriate units?

Balance Chemical equation is,

P₄ + 10 Cl₂ → 4 PCl₅

According to Balance Equation,

123.89 g (1 mole) of P₄ reacts to produce = 4 Moles of PCl₅

Then,

23 g of P₄ will react with excess Cl₂ to produce = X moles of PCl₅

Solving for X,

X = (4 mol * 23 g) : 123.89 g

X = 0.742 g of PCl₅

Result:

When 23 g of P₄ is reacted with excess Cl₂, 0.742 g of PCl₅ is produced.