Ask Question
10 July, 05:40

For the complete combustion of 5.6dm3 of a gaseuos hydrocarbon CxHy. 28.0dm3 of oxygen gas were used, 16.8dm3 of CO2 gas and 18.0gof liquid water were produced all gases measurement were made at stp. Determine the chemical formula of the hydrocarbon

+3
Answers (1)
  1. 10 July, 08:11
    0
    Answer is: the chemical formula of the hydrocarbon is C ₃H₈.

    Chemical reaction: CxHy + O₂ → xCO₂ + y/2H₂O.

    V (CxHy) = 5,6 dm³.

    V (O₂) = 28 dm³.

    V (CO₂) = 16,8 dm³.

    m (H₂O) = 18 g.

    Vm = 22,4 dm³/mol; molar volume.

    n (CxHy) = V (CxHy) : Vm.

    n (CxHy) = 5,6 dm³ : 22,4 dm³/mol = 0,25 mol.

    n (O₂) = 28 dm³ : 22,4 dm³/mol = 1,25 mol.

    n (CO₂) = 16,8 dm³ : 22,4 dm = 0,75 mol.

    n (H₂O) = 18 g : 18 g/mol = 1 mol.

    n (CxHy) : n (O₂) : n (CO₂) : n (H₂O) = 0,25 mol : 1,25 mol : 0,75 mol : 1 mol.

    n (CxHy) : n (O₂) : n (CO₂) : n (H₂O) = 1 : 5 : 3 : 4.

    Reaction is than: C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “For the complete combustion of 5.6dm3 of a gaseuos hydrocarbon CxHy. 28.0dm3 of oxygen gas were used, 16.8dm3 of CO2 gas and 18.0gof liquid ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers