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11 January, 09:22

A compound used to test for the presence of ozone in the stratosphere contains 96.2% thallium and 3.77% oxygen. What is it's empirical formula? If it's molecular mass 456.76 g/mol, what is it's molecular formula

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  1. 11 January, 11:05
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    Answer is: empirical formula is Tl₂O.

    If we use 100 grams of compound, tha:

    m (Tl) = 96.2% · 100 g : 100%.

    m (Tl) = 96.2 g.

    n (Tl) = m (Tl) : M (Tl).

    n (Tl) = 96.2 g : 204.4 g/mol.

    n (Tl) = 0.47 mol.

    m (O) = 3.77 g.

    n (O) = m (O) : M (O).

    n (O) = 3.77 g : 16 g/mol.

    n (Ag) = 0.235 mol.

    n (Tl). n (O) = 0.47 mol : 0.235 mol / 0.235.

    n (Tl). n (O) = 2 : 1.

    M (Tl ₂O) = 204.4 g/mol · 2 + 16 g/mol = 424.8 g/mol.

    M (compound) = 456. 8 g/mol - 424.8 g/mol = 32 g/mol (2 oxygens); Tl₂O₃.
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