Calculate the nuclear binding energy for 5525mn in megaelectronvolts per nucleon (mev/nucleon).

To solve this question, let us first calculate how much all the nucleons will weigh when they are apart, that is:

Mass of 25 protons = 25 (1.0073) = 25.1825 amu

Mass of neutrons = (55-25) (1.0087) = 30.261 amu

So, total mass of nucleons = 30.261+25.1825 = 55.4435 amu

Now we subtract the mass of nucleons and mass of the Mn nucleus:

55.4435 - 54.938 = 0.5055 amu

This difference in mass is what we call as the mass defect of a nucleus. Now we calculate the binding energy using the formula:

E=mc^2

But first convert mass defect in units of SI (kg):

Δm = 0.5055 amu = (0.5055) / (6.022x10^26)

Δm = 8.3942x10^-28 kg

Now applying the formula,

E=Δm c^2

E = (8.3942x10^-28) (3x10^8) ^2

E=7.55x10^-11 J

Convert energy from Joules to mev then divide by total number of nucleons (55):

E = 7.55x10^-11 J * (6.242x10^12 mev / 1 J) / 55 nucleons

E = 8.57 mev / nucleon