Pentacarbonyliron (0) (fe (co) 5) reacts with phosphorous trifluoride (pf3) and hydrogen, releasing carbon monoxide: fe (co) 5+2pf3+h2→fe (co) 2 (pf3) 2 (h) 2+3co if 6.0 g of fe (co) 5 reacts with 4.0 g of pf3 and 4.0 g of h2, which is the limiting reagent?

Question

Chemistry

Debree

13 December, 01:39

Pentacarbonyliron (0) (fe (co) 5) reacts with phosphorous trifluoride (pf3) and hydrogen, releasing carbon monoxide: fe (co) 5+2pf3+h2→fe (co) 2 (pf3) 2 (h) 2+3co if 6.0 g of fe (co) 5 reacts with 4.0 g of pf3 and 4.0 g of h2, which is the limiting reagent?

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Answers (1)

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Martha Barry · Answer 1

The limiting reactant can be determined by calculating the moles supplied / moles stoich ratio and the lowest is the limiting reactant.

Fe (CO) 5 ratio = [6 g / 195.9 g/mol] / 1

Fe (CO) 5 ratio = 0.0306

PF3 ratio = [4 g / 87.97 g/mol] / 2

PF3 ratio = 0.0227

H2 ratio = [4 g / 2 g/mol] / 1

H2 ratio = 2

We can see that PF3 has the lowest ratio, so it is the limiting reactant.