Em 150 gramas de alumínio, quantos átomos deste elemento estão presentes?

Dados:MM (AI) = 27 gmol-¹

Número de avogadro = 6,02 x 10²³

The question in English:

In 150 grams of aluminum, how many atoms of this element are present?

dа ta: MM (AI) = 27 g mol-1

Number of avogadro = 6.02 x 10²³

Answer:

Moles (mol) = mass (g) / molar mass (g/mol)

Mass of Al is given as 150 g.

Hence, moles of Al = 150 g / 27 g/mol = 5.56 mol

According to the Avogadro number, 1 mole of substance has 6.02 x 10²³ of particles.

Hence, 1 mole of Al = 6.02 x 10²³ of Al atoms

Then, atoms in 5.56 mol of Al = 6.02 x 10²³ mol⁻¹ x 5.56 mol

= 3.34712 x 10²⁴

Hence, 150 g of Al have 3.34712 x 10²⁴ of atoms.