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7 June, 04:18

When 8.21 l of c3h8 (g) burn in oxygen, how many liters of oxygen are consumed? all gas volumes are measured at the same temperature and pressure but not at stp?

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  1. 7 June, 05:45
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    8.21 L of C3H8 (g) Lets take c as the molar volume at that temperature.

    c L 5c L

    C3H8 (g) + 5O2 (g) - - > 3CO2 + 4H2O + Q

    8.21 L x L

    x = (8.21 * 5c) / c = 8.21 * 5 = 41.05 L O2 consumed for a 100% yield.
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