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7 May, 10:50

What is the pressure exerted by 1.2 mol of a gas with a temperature of 20.°c and a volume of 9.5 l?

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  1. 7 May, 11:23
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    Let's assume that the gas is an ideal gas. Then we can use ideal gas equation,

    PV = nRT

    Where,

    P = Pressure of the gas (Pa)

    V = volume of the gas (m³)

    n = number of moles (mol)

    R = Universal gas constant (8.314 J mol ⁻¹ K⁻¹)

    T = temperature in Kelvin (K)

    The given data for the gas is,

    P = ?

    V = 9.5 L = 9.5 x 10 ⁻³ m³

    T = (273 + 20) K = 293 K

    R = 8.314 J mol ⁻¹ K⁻¹

    n = 1.2 mol

    by applying the formula,

    P x 9.5 x 10⁻³ m³ = 1.2 mol x 8.314 J mol⁻¹ K⁻¹ x 293 K

    P = 307705.5 Pa

    P = 3.08 x 10 ⁵ Pa

    Hence, the pressure of the gas is 3.08 x 10⁵ Pa.
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