How many nitrogen atoms are present in 0.150 mol of zn (no3) 2?

First calculate number of Nitrogen atoms contained by 1 mole of Zn (NO₃) ₂,

As one formula unit of Zn (NO₃) ₂ contains 2 Nitrogen atoms, then one mole of Zn (NO₃) ₂ will contain,

= 2 * 6.022 * 10²³

= 1.20 * 10²⁴ Atoms of Nitrogen / mole

Now, calculate number of Nitrogen Atoms in 0.150 moles of Zn (NO₃) ₂.

As,

1 mole of Zn (NO₃) ₂ contained = 1.20 * 10²⁴ atoms of N

Then,

0.15 mole of Zn (NO₃) ₂ will contain = X atoms of N

Solving for X,

X = (0.15 mol * 1.20 * 10²⁴ atom) : 1 mol

X = 1.80 * 10²⁴ Atoms of Nitrogen

Result:

So, 0.15 mole of Zn (NO₃) ₂ contains 1.80 * 10²⁴ atoms of Nitrogen.