Ask Question
12 August, 10:48

How much energy is evolved during the formation of 197 g of fe, according to the reaction below? fe2o3 (s) + al (s) → al2o3 (s) + fe (s) δh°rxn = - 852 kj?

+2
Answers (1)
  1. 12 August, 14:41
    0
    Answer is: 1,51·10³ kJ is evolved during the formation.

    Chemical reaction: Fe₂O₃ (s) + Al (s) → Al₂O₃ (s) + Fe (s); ΔH°rxn = - 852 kJ.

    m (Fe) = 197 g.

    n (Fe) = m (Fe) : M (Fe).

    n (Fe) = 197 g : 55,85 g/mol.

    n (Fe) = 3,527 mol.

    Use proportion: 2 mol (Fe) : - 854 kJ = 3,527 mol (Fe) : ΔH°rxn.

    ΔH°rxn = - 854 kJ · 3,527 mol : 2 mol.

    ΔH°rxn = - 1510 kJ = - 1,51·10³ kJ.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “How much energy is evolved during the formation of 197 g of fe, according to the reaction below? fe2o3 (s) + al (s) → al2o3 (s) + fe (s) ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers