An empty 3.00 l bottle weighs 1.70 kg. filled with a certain wine, it weighs 4.72 kg. the wine contains 11.5% ethyl alcohol by mass. how many grams of ethyl alcohol are there in 250.0 ml of this wine?

Given:

m₁ = 1.70 kg, mass of the empty 3.00 L bottle

m₂ = 4.72 kg, the mass of the bottle and wine.

The mass of the wine is

m = m₂ - m₁ = 4.72 - 1.70 = 3.02 kg

Because the volume of the wine is 3.00 L, its density may be expressed as

(3.02 kg) / (3.00 L) = 1.0067 kg/L

The amount (density) of ethyl alcohol in the wine is

0.115 * (1.0067 kg/L) = 0.1158 kg/L

In 250 mL of this wine, the mass of ethyl alcohol is

(250 x 10⁻³ L) * (0.1158 kg/L) = 0.02895 kg = 28.95 g

Answer: 28.95 g