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29 August, 11:39

A 0.500-l sample of gas is at a pressure of 625 mm hg. what must the pressure be (in atm), at constant temperature, if the volume is changed to 925 ml?

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  1. 29 August, 12:22
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    Since temperature is held constant; Boyle's law can be expressed as: P 1 * V 1 = P 2 * V 2

    Where P1 = 625 and V1 = 0.5 L

    V2 = 925 * 10^ (-3) = 0.925 L and P2 = ?

    So P2 = (P1 * V1) / P2

    P2 = (625 * 0.5) / 0.925

    P2 = 337.83 my hg
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