What volume of 18 m sulfuric acid must be used to prepare 1.80 l of 0.215 m h2so4?

The rule that we will use to solve this question is:

(M*V) 1 = (M*V) 2 where:

M is the molarity and V is the volume

We are given that:

M1 = 18 m

M2 = 0.125 m

V2 = 1.8 l

we need to find V1

So, we will just substitute in the above equation to get V1 as follows:

18 (V1) = 0.125 (1.8)

V1 = 0.0125 liters