The pressure in a sealed plastic container is 108 kPa at 41 degrees Celsius. What is the pressure when the temperature drops to 22 degrees Celsius? Assume that the volume has not changed.

Initial conditions:

pressure=p1=108 kpa

temperature=T1=41 °C

Finial conditions:

pressure=p2=?

temperature=T2=22 °C

According to general gas equation;

p1*v1/T1 = p2*v2/T2

As, Volume is constant

p1/T1 = p2/T2

108/41 = p2/22

p2 = 57.95 kpa