How many liters of chlorine gas can be produced when 0.98 l of hcl react with excess o2 at stp? 4hcl (g) + o2 (g) - > 2cl2 (g) + 2h2o (g) ?

Question

Chemistry

Sarai Mcneil

12 September, 10:27

How many liters of chlorine gas can be produced when 0.98 l of hcl react with excess o2 at stp? 4hcl (g) + o2 (g) - > 2cl2 (g) + 2h2o (g) ?

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Answers (1)

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Belinda · Answer 1

The balanced equation for the reaction is as follows;

4HCl + O₂ - - - > 2Cl₂ + 2H₂O

stoichiometry of HCl to Cl₂ is 4:2

Avagadros law states that volume is proportional to number of moles of gas when pressure and temperature are constant

therefore volume ratio is equal to the molar ratio

therefore molar ratio of HCl to Cl₂ is 4:2

volume of HCl reacted - 0.98 L

therefore volume of Cl₂ formed - 0.98 L / 2 = 0.49 L