Ask Question
17 April, 21:03

A sample of aluminum chloride (alcl3) has a mass of 37.2 g.

a. how many aluminum ions are present?

b. how many chloride ions are present?

c. what is the mass in grams of one formula unit (molecule) of aluminum chloride?

+2
Answers (1)
  1. 17 April, 22:27
    0
    C)

    The mass in grams of one formula unit of Aluminum Chloride is 133.34 g/mol.

    A)

    Aluminium Ions in 37.2 g of AlCl ₃:

    First convert mass into moles,

    As,

    Moles = Mass / M. mass

    Putting Values,

    Moles = 37.2 g : 133.34 g/mol

    Moles = 0.278 moles

    As one mole contain 6.022 * 10²³ Al³⁺ Ions, so 0.278 moles will contain,

    = 6.022 * 10²³ * 0.278 mol

    = 1.67 * 10²³ Al³⁺ Ions

    B)

    As one mole of AlCl₃ contain (3 * 6.022 * 10²³ = 1.80 * 10²⁴) Ions, so 0.278 mole will contain,

    = 1.80 * 10²⁴ * 0.278

    = 5.022 * 10²³ Cl⁻ Ions
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A sample of aluminum chloride (alcl3) has a mass of 37.2 g. a. how many aluminum ions are present? b. how many chloride ions are present? ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers