Calculate the volume of dry co2 produced at body temperature (37 ∘c) and 0.960 atm when 24.0 g of glucose is consumed in this reaction.

The balanced equation for the above reaction is as follows;

C₆H₁₂O₆ + 6O₂ - - > 6CO₂ + 6H₂O

molar ratio of glucose to CO₂ is 1:6

the mass of glucose reacted - 24.0 g

Number of glucose moles reacted - 24.0 g / 180 g/mol = 0.133 mol

Number of CO₂ formed when 0.133 mol of glucose reacted - 0.133 x 6 = 0.798 mol

since CO₂ is a gas we can use the ideal gas law equation to find the volume occupied

PV = nRT

where P - pressure - 0.960 atm x 101 325 Pa / atm = 97 272 Pa

n - number of moles - 0.798 mol

R - universal gas constant - 8.314 Jmol⁻¹K⁻¹

T - temperature in Kelvin - 273 + 37 °C = 310 K

substituting the values in the equation

97 272 Pa x V = 0.798 mol x 8.314 Jmol⁻¹K⁻¹ x 310 K

V = 21.1 dm³

volume occupied by CO₂ is 21.1 dm³