23492u undergoes alpha decay. what is the atomic number of the resulting element.

Question

Chemistry

Guest

23 January, 04:48

23492u undergoes alpha decay. what is the atomic number of the resulting element.

+1

Answers (1)

Know the Answer?

Lamont Mann · Answer 1

Alpha decay involves the loss of an alpha particle, aka a helium nucleus. This results in the mass number of the original element decreasing by 4 and the atomic number decreasing by 2. Assuming 23942u is uranium (92), the resulting element's atomic number is 90, making it thorium.