Whitney's lung capacity was measured as 3.2 l at a body temperature of 37 ∘c and a pressure of 747 mmhg. how many moles of oxygen is in her lungs if air contains 21% oxygen?

Question

Chemistry

Barrett Skinner

30 August, 11:09

Whitney's lung capacity was measured as 3.2 l at a body temperature of 37 ∘c and a pressure of 747 mmhg. how many moles of oxygen is in her lungs if air contains 21% oxygen?

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Kaylie Glenn · Answer 1

Whitney has 0.026 moles of O2 in her lungs. The ideal gas law is PV = nRT where P = Pressure V = volume n = Number of moles R = Ideal Gas Constant (0.082057338 L*atm / (K*mol)) T = Absolute temperature Since a mmHg is 1/760 atm, the pressure is 747/760 atm = 0.982894737 atm Converting 37C to K, 37 + 273.15 = 310.15 K Now let's take the ideal gas equation, solve for n, the substitute the known values and solve. PV = nRT PV/RT = n (0.982894737 atm) (3.2 L) / ((0.082057338 L*atm / (K*mol)) 310.15 K) = n (3.145263158 atm*L) / (25.45008338 L*atm/mol) = n 0.123585574 mol = n So there's 0.123585574 moles of gas particles in Whitney's lungs. Let's get the moles of oxygen 0.123585574 mol * 0.21 = 0.02595297 mol Rounding to 2 significant figures gives 0.026 moles.