2.0 grams of ZnSO4 reacts completely with Li2CO3; how many grams of Li2SO4 would be produced?

Moles of ZnSO4 = Mass/Mr

= 2 / (65.4 + 32.1 + (16 x 4))

= 0.012383 ... mol

Since there is no chemical equation provided, I will assume that the ratio of ZnSO4:Li2CO3 is 1:1

Therefore there are 0.012383 mil of Li2SO4 as well

So the mass would be Moles x Mr = 0.012383 ... x ((6.9 x 2) + 32.1 + (4x16))

= 1.360 g of Li2SO4 produced